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Yachtmaster School / Tides

Estimate the effect of a tidal stream

See how a current changes progress using simple along-track examples.

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Our goal today

Distinguish water-level predictions from stream information and estimate a simple time penalty.

What you’ll practise

  • Adding directly aligned boat and stream velocities
  • Calculating passage time from ground speed
  • Understanding cross-stream vectors and local slack timing

Each question includes a custom diagram, the reasoning behind the answer, an explanation of the other choices and a follow-up exercise. Try the quiz first, or use the study view to read every answer.

01 / Learn

Height and movement are different

Tidal height describes water level. A tidal stream describes moving water, with direction and speed. Information about one does not automatically give you the other. Use the appropriate local stream information rather than treating high water as a universal promise of slack water.

02 / Learn

Use a deliberately simple model

Assume a yacht maintains 5 knots through the water. A constant 2-knot stream directly along its intended track gives 7 knots over the ground when favourable, or 3 knots when opposed. A fictional 21-mile leg then takes 3 hours with the stream or 7 hours against it.

03 / Learn

Know when the shortcut stops working

Those sums assume a straight line, constant speeds and a stream directly aligned with the track. A cross-stream needs a vector approach, not simple addition. Real streams change with place and time. Break a passage into useful stages and revisit your estimates as actual progress becomes available.

Your two-minute exercise

Calculate a 12-mile leg at 4 knots through the water with a constant 1-knot stream directly against you. Then explain why a cross-stream is a different problem.

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Source check: . Scenarios and quiz questions are original YouSail practice material. Editorial policy.

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Have a go

Tidal Streams & Passage Planning Quiz

10 illustrated questions. Worked explanations and practical follow-ups for every answer.

5 knots through the water plus a directly favourable 2-knot stream gives…
A yacht’s 5-knot through-water arrow and a directly aligned favourable 2-knot stream arrow; ground speed is unknown.
A favourable streamIllustrative · not to scale · tap to enlarge ↗
Read the answer and explanation

Answer: 7 knots over ground

Why this answer works

In this aligned, constant-speed model, 5 + 2 = 7 knots over ground.

Why the other choices fall short

Subtracting would describe an opposing stream; multiplying 5 by 2 has no physical basis here. Directly aligned favourable velocities add in this simplified model.

Put it into practice

Draw both arrows in the same direction and add 5 + 2 = 7 knots. State explicitly that this is speed over the ground, not a new through-water speed.

The same stream directly opposes the boat. Speed over ground is…
A yacht’s 5-knot through-water arrow opposed by a 2-knot stream; ground speed is unknown.
An opposing streamIllustrative · not to scale · tap to enlarge ↗
Read the answer and explanation

Answer: 3 knots

Why this answer works

In this model, 5 − 2 = 3 knots over ground.

Why the other choices fall short

Seven knots adds a favourable stream when the question says opposing. Dividing by two has no basis in this velocity relationship.

Put it into practice

Draw the current arrow opposite the boat's through-water arrow. Subtract 2 from 5 and check that an adverse stream makes progress slower, not faster.

At 3 knots over ground, a 21-mile leg takes…
A fictional 21-nautical-mile leg at 3 knots over the ground, with travel time unknown.
Calculate the passage timeIllustrative · not to scale · tap to enlarge ↗
Read the answer and explanation

Answer: 7 hours

Why this answer works

Time = distance ÷ speed, so 21 ÷ 3 = 7 hours.

Why the other choices fall short

Three hours would cover 9 nm and five hours would cover 15 nm at 3 knots. Neither reaches the stated 21 nm.

Put it into practice

Use time = 21 ÷ 3 = 7 hours. Multiply 7 × 3 to verify the distance, then consider what happens if the assumed ground speed changes.

Can the same simple addition handle a stream across the track?
A forward boat-motion arrow and a perpendicular stream arrow, with no resulting course drawn.
When the stream crossesIllustrative · not to scale · tap to enlarge ↗
Read the answer and explanation

Answer: No; direction must be included in a vector solution

Why this answer works

The along-track shortcut is not valid for a cross-stream.

Why the other choices fall short

Knots supplies a unit of speed but not a direction. Adding the full cross-stream speed along the track would treat sideways motion as forward progress.

Put it into practice

Draw the boat and stream arrows with their actual directions. Use a vector method taught in navigation training rather than the directly aligned shortcut.

A tide table gives a high-water time. What does that alone tell you about local slack water?
Separate clock cards labelled high water and slack water, without hands or a claimed timing relationship.
Two different tide questionsIllustrative · not to scale · tap to enlarge ↗
Read the answer and explanation

Answer: It does not establish the local stream timing

Why this answer works

Stream timing depends on the location and must be checked using relevant information.

Why the other choices fall short

High-water time describes the vertical tide at a place. A universal one-hour offset or exact coincidence does not follow for a different local stream.

Put it into practice

Find the relevant stream information and its reference time. Check any stated offsets and location before using them for a passage or gate.

Which assumption underpins the worked calculation?
Straight aligned boat and stream arrows, labelled as the assumptions of a simple model.
The model’s assumptionsIllustrative · not to scale · tap to enlarge ↗
Read the answer and explanation

Answer: The stream stays constant and directly aligned with the track

Why this answer works

The arithmetic is a simplified aligned-current exercise, not a full tidal passage plan.

Why the other choices fall short

Ignoring weather is not a mathematical requirement, and high water is not implied by a particular stream. The calculation depends on the specified constant, aligned velocities.

Put it into practice

Write those assumptions beside the answer. On a real passage, reassess when the current direction, strength or vessel speed no longer matches them.

In a simplified straight-line exercise, the boat makes 5 knots through the water and a 2-knot stream runs directly against it. What speed over the ground results?
Opposing arrows show a boat’s five knots through the water and a two-knot stream directly against it.
Directly opposing streamIllustrative · not to scale · tap to enlarge ↗
Read the answer and explanation

Answer: 3 knots

Why this answer works

For this exactly opposing stream, subtract: 5 − 2 = 3 knots. This shortcut applies to the stated straight-line case, not to a stream crossing the course at an angle.

Why the other choices fall short

Five knots ignores the opposing current, seven knots uses the wrong direction and 2.5 knots divides rather than subtracts. Only 5 − 2 represents the stated model.

Put it into practice

Use a sketch to check the sign before doing the arithmetic. Confirm that the result is ground speed and that no cross-track component has been introduced.

A fictional 24 nm leg has 4 knots through the water and a constant 2-knot stream directly with the boat. How long does it take in this simplified model?
Two aligned arrows show four knots through the water and a two-knot following stream for a 24 nautical mile exercise.
Stream with the boat: 24 nmIllustrative · not to scale · tap to enlarge ↗
Read the answer and explanation

Answer: 4 hours

Why this answer works

Ground speed = 4 + 2 = 6 knots. Time = 24 ÷ 6 = 4 hours. The exercise assumes a constant, directly following stream; real stream strength and direction can change along the route.

Why the other choices fall short

Six hours ignores the following stream; twelve hours uses an opposing one. Three hours requires 8 knots over ground, which is not supplied by these inputs.

Put it into practice

Calculate ground speed first, 4 + 2 = 6 knots, then 24 ÷ 6 = 4 hours. Keep the two steps visible so an error in either one can be traced.

You find the time of high water for a port, but need the time of slack stream in a nearby channel. What should you consult?
Separate clocks represent port high-water time and an unknown slack-stream time in a nearby channel.
Height time and stream timeIllustrative · not to scale · tap to enlarge ↗
Read the answer and explanation

Answer: Relevant local tidal-stream information for the channel

Why this answer works

Height and horizontal flow are related but their timings are location-dependent. Use applicable stream data and its reference times rather than assuming high water and slack coincide.

Why the other choices fall short

Neither an exact match nor a fixed one-hour delay is established by the high-water table. Tide height alone also does not give a complete horizontal-flow direction.

Put it into practice

Use local channel stream data for slack timing. Read how its times relate to the named reference port and the date of the passage.

For one hour in a simplified model, a boat moves 4 nm north through the water while the stream carries it 3 nm east. What straight-line distance over the ground separates start and finish?
A right-angle displacement sketch shows four nautical miles north and three nautical miles east with the diagonal labelled unknown.
One hour: north and eastIllustrative · not to scale · tap to enlarge ↗
Read the answer and explanation

Answer: 5 nm

Why this answer works

The displacements form perpendicular sides of a right triangle. The ground displacement is the diagonal: square root of (4² + 3²) = square root of 25 = 5 nm. It is not a simple sum along one line.

Why the other choices fall short

Seven adds perpendicular distances as if they share a direction; one subtracts them as if they oppose. Four ignores the eastward displacement entirely.

Put it into practice

Sketch north and east axes and join the start to the final point. This exercise assumes constant perpendicular movements for one hour; real current problems need the actual directions and timing.

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Practice only: this quiz is not an official RYA examination or an assessment of practical competence. Leaving mid-quiz starts that attempt again.

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